How do you solve #\frac { 1} { 6} b + 10= 15#?

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Answer 1 · 2017-05-19T13:08:36

See a solution process below:

First, subtract #color(red)(10)# from each side of the equation to isolate the #b# term while keeping the equation balanced:

#1/6b + 10 - color(red)(10) = 15 - color(red)(10)#

#1/6b + 0 = 5#

#1/6b = 5#

Now, multiply each side of the equation by #color(red)(6)# to solve for #b# while keeping the equation balanced:

#color(red)(6) xx 1/6b = color(red)(6) xx 5#

#cancel(color(red)(6)) xx 1/color(red)(cancel(color(black)(6)))b = 30#

#b = 30#