Question

How do you multiply `(2m+3)(m-1)`?

Answer 1

`2m^2 +m -3`

Explanation:

First of all, we use the FOIL method, which helps when distributing factored binomials.
F: Multiply first terms of each parenthesis
O: Multiply the outside terms (first term of the first parenthesis and
last term of the second parenthesis)
I: Multiply the inside terms (last term of the first parenthesis and first term of the second parenthesis)
L: Multiply last terms of each parenthesis

Now, to the math:

`(2m+3)(m-1)`

F: `(2m) * (m) = 2m^2`

O: `(2m)*(-1) = -2m`

I: `(3)*(m) = 3m`

L: `(3)*(-1) = -3`

Now that we have all of our terms, we simplify to get the solution by adding like terms:

`(2m^2) + (-2m) + (3m) + (-3)`
= `2m^2 + (3m-2m) -3`
= `2m^2 +m -3`

Answer 2

`2m^2+m-3`

Explanation:

Each term in the second bracket is multiplied by each term in the first bracket as shown below.

`(color(red)(2m+3))(m-1)`

`=color(red)(2m)(m-1)color(red)(+3)(m-1)`

`=(color(red)(2m)xxm)+(color(red)(2m)xx-1)+(color(red)(3)xxm)+(color(red)(3)xx-1)`

`=2m^2+(-2m)+3m+(-3)`

`=2m^2-2m+3m-3`

`=2m^2+m-3`