How do you multiply (2m+3)(m-1)?

2 Answers
May 20, 2017

2m^2 +m -3

Explanation:

First of all, we use the FOIL method, which helps when distributing factored binomials.
F: Multiply first terms of each parenthesis
O: Multiply the outside terms (first term of the first parenthesis and
last term of the second parenthesis)
I: Multiply the inside terms (last term of the first parenthesis and first term of the second parenthesis)
L: Multiply last terms of each parenthesis

Now, to the math:

(2m+3)(m-1)

F: (2m) * (m) = 2m^2

O: (2m)*(-1) = -2m

I: (3)*(m) = 3m

L: (3)*(-1) = -3

Now that we have all of our terms, we simplify to get the solution by adding like terms:

(2m^2) + (-2m) + (3m) + (-3)
= 2m^2 + (3m-2m) -3
= 2m^2 +m -3

May 20, 2017

2m^2+m-3

Explanation:

Each term in the second bracket is multiplied by each term in the first bracket as shown below.

(color(red)(2m+3))(m-1)

=color(red)(2m)(m-1)color(red)(+3)(m-1)

=(color(red)(2m)xxm)+(color(red)(2m)xx-1)+(color(red)(3)xxm)+(color(red)(3)xx-1)

=2m^2+(-2m)+3m+(-3)

=2m^2-2m+3m-3

=2m^2+m-3