What are the asymptotes and removable discontinuities, if any, of #f(x)= 2/( e^(-6x) -4) #?
1 Answer
May 20, 2017
No removable discontinuities.
Asymptote:
Explanation:
Removable discontinuities are when
That leaves us finding the asymptotes (where the denominator = 0).
We can set the denominator equal to 0 and solve for
#e^(-6x)-4=0#
#e^(-6x)=4#
#-6x = ln4#
#x = -ln4/6 = -0.231#
So the asymptote is at
graph{2/(e^(-6x)-4) [-2.93, 2.693, -1.496, 1.316]}