How do you solve #16 = -d+6#?

Question

1069 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-05-21T17:08:55

See a solution process below:

First, subtract #color(red)(6)# from each side of the equation to isolate the #d# term while keeping the equation balanced:

#16 - color(red)(6) = -d + 6 - color(red)(6)#

#10 = -d + 0#

#10 = -d#

Now, multiply each side of the equation by #color(red)(-1)# to solve for #d# while keeping the equation balanced:

#color(red)(-1) xx 10 = color(red)(-1) xx -d#

#-10 = d#

#d = -10#