How do you solve #x+ x + 2+ x + 4= 240#?

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Answer 1 · 2017-05-22T22:17:30

See a solution process below:

First, group and combine like terms on the left side of the equation:

#x + x + 2 + x + 4 = 240# becomes:

#x + x + x + 2 + 4 = 240#

#(1x + 1x + 1x) + (2 + 4) = 240#

#(1 + 1 + 1)x + 6 = 240#

#3x + 6 = 240#

Next, subtract #color(red)(6)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#3x + 6 - color(red)(6) = 240 - color(red)(6)#

#3x + 0 = 234#

#3x = 234#

Now, divide each side of the equation by #color(red)(3)# to solve for #x# while keeping the equation balanced:

#(3x)/color(red)(3) = 234/color(red)(3)#

#(color(red)(cancel(color(black)(3)))x)/cancel(color(red)(3)) = 78#

#x = 78#