How do you solve #6x ^ { 2} - 7= 257#?

1 Answer
May 22, 2017

See a solution process below:

Explanation:

First, add #color(red)(7)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#6x^2 - 7 + color(red)(7) = 257 + color(red)(7)#

#6x^2 - 0 = 264#

#6x^2 = 264#

Next, divide each side of the equation by #color(red)(6)# to isolate #x^2# while keeping the equation balanced:

#(6x^2)/color(red)(6) = 264/color(red)(6)#

#(color(red)(cancel(color(black)(6)))x^2)/cancel(color(red)(6)) = 44#

#x^2 = 44#

Next, take the square root of each side of the equation to solve for #x# while keeping the equation balanced. Remember the square root of a number produces a positive and negative result:

#sqrt(x^2) = sqrt(44)#

#x = sqrt(4 xx 11)#

#x = +-2sqrt(11)#

Or

#x = +-6.633# rounded to the nearest thousandth.