Question

If 60.2 grams of Hg combines completely with 24.0 grams of Br to form a compound, what is the percent composition of Hg in the compound?

Answer 1

`%Hg=71.5%`

Explanation:

`%Hg="mass of mercury"/"mass of mercury and bromine"xx100%`

`=(60.2*g)/(60.2*g+24.0*g)xx100%=??%`

In such a binary compound, if you have the percentage by mass of one component, you also have the percentage by mass of the other component.