Question

Question #6c167

Answer 1

`y=log_0.75(2x+8)`

Explanation:

`y=0.5*(0.75)^x-4`
Switch x and y to find inverse:
`x=0.5*(0.75)^y-4`
`2x=0.75^y-8`
`2x+8=0.75^y`
`y=log_0.75(2x+8)`