How do you solve #1- 9x + 5( 2x - 3) \leq - 19#?

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Answer 1 · 2017-05-24T22:48:53

#x <= -5#

First, distribute the #5#.

#1-9x+color(blue)5(2x-3) <= -19#

#1-9x + color(blue)5*2x-color(blue)5*3 <= -19#

#1-9x + 10x - 15 <= -19#

Now combine like terms.

#color(red)1 - color(limegreen)(9x)+color(limegreen)(10x)-color(red)15 <= -19#

#color(limegreen)x - color(red)14 <= -19#

Finally, add #color(orange)14# to both sides.

#x-14+color(orange)14 <= -19 +color(orange)14#

#x <= -5#

Final Answer