Question

How do you solve `7x ^ { 3} + 5x - 2= 6x ^ { 3} + 5x - 3`?

Answer 1

`x=-1`

Explanation:

Let's reorganize your equation.

`7x^3+5x-2=6x^3+5x-3`
`7x^3+cancel(5x)-2=6x^3+cancel(5x)-3`
`7x^3-2=6x^3-3`
`7x^3-6x^3=-3+2`
`x^3=-1`
`x=root(3)(-1)=-1`

`x=-1`