How do you solve $7x ^ { 3} + 5x - 2= 6x ^ { 3} + 5x - 3$ ?

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Answer 1 · 2017-05-25T01:33:19

$x=-1$

Let's reorganize your equation.

$7x^3+5x-2=6x^3+5x-3$
$7x^3+cancel(5x)-2=6x^3+cancel(5x)-3$
$7x^3-2=6x^3-3$
$7x^3-6x^3=-3+2$
$x^3=-1$
$x=root(3)(-1)=-1$

$x=-1$

How do you solve 7x ^ { 3} + 5x - 2= 6x ^ { 3} + 5x - 37x ^ { 3} + 5x - 2= 6x ^ { 3} + 5x - 3?