What is the molarity of a #0.28mol# quantity confined to a volume of #2.6L#?

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Answer 1 · 2017-05-25T06:47:32

#"Molarity"="Moles of solute"/"Volume of soluton"..............#

And thus...........

#"Molarity"=(0.28*mol)/(2.6*L)=0.108*mol*L^-1............#

The quotient gives us the required units of concentration.....

#"moles of solute per volume of solution"#, i.e. #mol*L^-1#.

What is the molarity of a #0.28*mol# quantity confined to a volume of #2.6*L#?