How many oxygen ATOMS are present in a #25*g# mass of aluminum phosphate?

1 Answer
anor277
May 25, 2017

Approx. #0.82xxN_A# oxygen atoms, where #N_A=6.022xx10^23#.

Explanation:

#"Moles of aluminium phosphate"=(25*g)/(121.95*g*mol^-1)#

#=0.205*mol#

But given the molar quantity, and given the stoichiometry of #AlPO_4#, there are #4xx0.205*mol=0.820*mol# of #"oxygen atoms"#, i.e. #0.820*molxx6.022xx10^23*mol^-1=??# oxygen atoms...

What mass of oxygen does this molar quantity represent.

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