How do you solve #-7( 8m + 2) + 8> 106#?

1 Answer
May 25, 2017

See a solution process below:

Explanation:

First, subtract #color(red)(8)# from each side of the inequality to isolate the term in parenthesis while keeping the inequality balanced:

#-7(8m + 2) + 8 - color(red)(8) > 106 - color(red)(8)#

#-7(8m + 2) + 0 > 98#

#-7(8m + 2) > 98#

Next, divide each side of the inequality by #color(blue)(-7)# to eliminate the need for parenthesis while keeping the inequality balanced. However, because we are multiplying or dividing an inequality by a negative number we must reverse inequality operator:

#(-7(8m + 2))/color(blue)(-7) color(red)(<) 98/color(blue)(-7)#

#(color(red)(cancel(color(black)(-7)))(8m + 2))/cancel(color(blue)(-7)) color(red)(<) -14#

#8m + 2 color(red)(<) -14#

Then, subtract #color(red)(2)# from each side of the inequality to isolate the #m# term while keeping the inequality balanced:

#8m + 2 - color(red)(2) color(red)(<) -14 - color(red)(2)#

#8m + 0 color(red)(<) -16#

#8m color(red)(<) -16#

Now, divide each side of the inequality by #color(red)(8)# to solve for #m# while keeping the inequality balanced:

#(8m)/color(red)(8) < -16/color(red)(8)#

#(color(red)(cancel(color(black)(8)))m)/cancel(color(red)(8)) < -2#

#m < -2#