How do you solve #17= 2x + 5#?

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Answer 1 · 2017-05-25T23:15:09

The answer is #x = 6#.

You subtract 5 from #17=2x+5# on both sides to get #12=2x#.

Divide both sides by 2 to get #x=6#.

Answer 2 · 2017-05-25T23:17:15

See a solution process below:

First, subtract #color(red)(5)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#17 - color(red)(5) = 2x + 5 - color(red)(5)#

#12 = 2x + 0#

#12 = 2x#

Now, divide each side of the equation by #color(red)(2)# to solve for #x# while keeping the equation balanced:

#12/color(red)(2) = (2x)/color(red)(2)#

#6 = (color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2))#

#6 = x#

#x = 6#