Question

Question #a16c1

Answer 1

The length is 15 meters and the width is 9 meters.

Explanation:

If we set this up as an algebraic equation, the length, `l`, and the width, `w`, would be set up as `l = w+6`

Provided `A=l*w`, we can substitute `l` as `w+6` so that `A=(w+6)*w=w^2+6w`

If your Area, `A` is `135 m^2`. we plug it in so that `135 = w^2+6w`

Subtract `135` from both sides to get `0=w^2+6w-135`. If we factor this we get `(w+15)(w-9)=0`, so `w=-15 or 9`. Since distance can't be negative, `w=9`

If `l=w+6`, `l=9+6=15`

So the width is 9 meters and the length is 15 meters.