How do you divide #(2x ^ { 2} - 5x - 4) -: ( x - 3)#?

1 Answer

quotient #= 2x + 1#
remainder #= 1#

Explanation:

First you divide #2x^2# by #x# and get #= 2x#.

#2x# multiplied by #x - 3# is #=2x^2-6x#

#frac{2x^2 - 5x + 4}{x - 3} = 2x + frac{2x^2 - 5x + 4 - (2x^2 - 6x)}{x - 3}#

The remainder is #x + 4#, which divided by #x + 3# gives #1# and remainder #1# too.

#frac{2x^2 - 5x + 4}{x - 3} = 2x + 1 + frac{1}{x - 3}#

You could also use Briot Ruffini.