How do you solve #25x ^ { 2} + 25x = 6#?

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Answer 1 · 2017-05-26T14:53:43

#-6/5 & 1/5#

Given, #25x^2+25x=6#

#rArr 25x^2+25x-6 = 0#

#rArr 25x^2+(30-5)x-6=0#

#rArr 25x^2+30x-5x-6=0#

#rArr 5x(5x+6)-1(5x+6)=0#

#rArr (5x+6)(5x-1)=0#

#rArr (5x+6) =0, (5x-1)=0#

#rArr x = -6/5 & 1/5#