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Answer 1 · 2017-05-27T07:24:43

Length = 10.9 inch & width = 2.9 inch

Let the width be x inch. So length = (x + 8) inches.

Now as per questions, #x( x + 8 ) = 2{x+(x+8)} +4#

#rArr x^2+8x= 4x+16+4#

#rArr x^2+4x-20 = 0#

#rArr x = [-b+- sqrt(b^2-4ac)]/[2a]# where b = 4, a = 1 & c = - 20

#rArr x = [-4+- sqrt{4^2-4*1*(-20)}]/(2*1)#

#rArr x = [ -4 +- sqrt(16+80)]/2#

#rArr x = [-4 +- sqrt96]/2#

#rArr x = [-4 +- 9.8]/2#

#rArr x = 2.9 or - 13.8# [ Note : width cannot be negative]

#rArr x = 2.9#

Hence width = 2.9 inch & length = (8 + 2.9) = 10.9 inch