Question

Question #5d437

Answer 1

`b->1/3`

Explanation:

There are three groups of people. Let them be `g_1"; "g_2"; "g_3`
Let the total count be `g_t`

.........................................................................................................
One half of the employees earn:

`g_1=1/2xxg_t >18000`

The remainder at this point is `1/2g_t`
.............................................................................................................
One third of the remainder earn:

`g_2->15000<[1/3(1/2g_t)]<18000`
............................................................................................................

What part of the staff earn less than 15000

This is a question just about fractions

The remainder is `" "g_3=[1-1/2-(1/3xx1/2)]g_t`

`1/2-(1/3xx1/2)`

`1/2-1/6`

`3/6-1/6" "=" "2/6" "=" "1/3`