How do you solve $\frac{x + 2}{3} = \frac{4 x + 1}{11}$ $\frac { x + 2} { 3} = \frac { 4x + 1} { 11}$ ?

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Answer 1 · 2017-05-28T02:57:45

$x = 19$ $x=19$

First, simplify the equation by cross multiplying:

$\frac{x + 2}{3} = \frac{4 x + 1}{11}$ $(x+2)/3=(4x+1)/11$

$(4 x + 1) \cdot 3 = (x + 2) \cdot 11$ $(4x+1)*3=(x+2)*11$

Or if you prefer the long way:

$\frac{x + 2}{3} = \frac{4 x + 1}{11}$ $(x+2)/3=(4x+1)/11$

$(x+2)/cancel(3)*cancel(3)=(4x+1)/11*3$
$(x+2)*11=(4x+1)/cancel(11)*3*cancel(11)$
$(4x+1)*3=(x+2)*11$

Then, distribute the coefficients:

$(4x+1)*3=(x+2)*11$

$12x+3=11x+22$

$x=22-3=19$

$x=19$

How do you solve \frac { x + 2} { 3} = \frac { 4x + 1} { 11}x+23=4x+111\frac { x + 2} { 3} = \frac { 4x + 1} { 11}?