How do you solve #\frac { x + 2} { 3} = \frac { 4x + 1} { 11}#?

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Answer 1 · 2017-05-28T02:57:45

#x=19#

First, simplify the equation by cross multiplying:

#(x+2)/3=(4x+1)/11#

#(4x+1)*3=(x+2)*11#

Or if you prefer the long way:

#(x+2)/3=(4x+1)/11#

#(x+2)/cancel(3)*cancel(3)=(4x+1)/11*3#
#(x+2)*11=(4x+1)/cancel(11)*3*cancel(11)#
#(4x+1)*3=(x+2)*11#

Then, distribute the coefficients:

#(4x+1)*3=(x+2)*11#

#12x+3=11x+22#

#x=22-3=19#

#x=19#