Question

How do you write the equation `y+2=7/8(x-3)` in standard form?

Answer 1

That equation in standard form is `y= 7/8x-37/8`

Explanation:

First, you can distribute the `7/8` to the `x` and the `-3`:

`y+2=7/8x-21/8`

After that subtract both sides by two:

`y+2-2=7/8x-21/8-2`

`y=7/8x-21/8-16/8`

`y= 7/8x-37/8`

Answer 2

`7x-8y=37`

Explanation:

`"the equation of a line in "color(blue)"standard form"` is.

`color(red)(bar(ul(|color(white)(2/2)color(black)(Ax+By=C)color(white)(2/2)|)))`
where A is a positive integer and B, C are integers.

`"rearrange " y+2=7/8(x-3)" into this form"`

`rArry+2=7/8x-21/8larrcolor(red)" distributing"`

`"subtract " 7/8x" from both sides"`

`y+2-7/8x=cancel(7/8x)cancel(-7/8x)-21/8`

`rArry+2-7/8x=-21/8`

`"subtract 2 from both sides"`

`ycancel(+2)cancel(-2)-7/8x=-21/8-2`

`rArry-7/8x=-37/8`

`"multiply through by " -8`

`rArr7x-8y=37larrcolor(red)" in standard form"`