Question

Question #c25c8

Answer 1

In it's lowest form, the expression equals `(3(x+3))/(2x+1)`, or `(3x+9)/(2x+1)`

Explanation:

First off, we should factor `(3x²-27)/(2x²-5x-3)`, and this produces:

`(3(x-3)(x+3))/((2x+1)(x-3))`

Now cancel out the term `(x-3)` from the numerator and denominator:

`(3cancel((x-3))(x+3))/((2x+1)cancel((x-3)))`

`(3(x+3))/(2x+1)`

From here you can distribute the `3` to form `3x+9` or leave it as that.