How do you simplify #(6v^{2}+2v-9)(4-5v^{2})#?

1 Answer
May 30, 2017

See a solution process below:

Explanation:

To simplify this expression we need to multiply the two terms. To multiply these two terms you multiply each individual term in the left parenthesis by each individual term in the right parenthesis.

#(color(red)(6v^2) + color(red)(2v) - color(red)(9))(color(blue)(4) - color(blue)(5v^2))# becomes:

#(color(red)(6v^2) xx color(blue)(4)) - (color(red)(6v^2) xx color(blue)(5v^2)) + (color(red)(2v) xx color(blue)(4)) - (color(red)(2v) xx color(blue)(5v^2)) - (color(red)(9) xx color(blue)(4)) + (color(red)(9) xx color(blue)(5v^2))#

#24v^2 - 30v^4 + 8v - 10v^3 - 36 + 45v^2#

We can now group and combine like terms:

#-30v^4 - 10v^3 + 24v^2 + 45v^2 + 8v - 36#

#-30v^4 - 10v^3 + (24 + 45)v^2 + 8v - 36#

#-30v^4 - 10v^3 + 69v^2 + 8v - 36#