Question

Question #a1b5e

Answer 1

`p(-2) = 0`
`p(x + n) = x^2 + (2n+2)x + n(n + 2)`

Explanation:

`p(x) = x^2 + 2 x`

`p(-2) = (-2)^2 + 2(-2) = 0`

`p(x + n) = (x + n)^2 + 2 (x + n)`

`= x^2 + 2n x + n^2 +2x +2n`

`= x^2 + (2n+2)x + n(n + 2)`