Ho do you solve #2-3x=-x-8#?

1 Answer
Jim G.
May 30, 2017

#x=5#

Explanation:

#"add 3x to both sides"#

#2cancel(-3x)cancel(+3x)=-x+3x-8#

#rArr2=2x-8#

#"add 8 to both sides"#

#2+8=2xcancel(-8)cancel(+8)#

#rArr2x=10#

#"divide both sides by 2"#

#rArrx=10/2=5#

#color(blue)"As a check"#

Substitute this value into the equation and if both sides are equal then it is the solution.

#"left side "=2-(3xx5)=2-15=-13#

#"right side "=-5-8=-13#

#rArrx=5" is the solution"#

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