Question

How do you evaluate `\frac { 12- 3y } { 2} + v \frac { 2y - 4} { y }` for `y=3`?

Answer 1

See a solution process below:

Explanation:

For each occurrence of `color(red)(y)` we need to substitute `color(red)(3)` and then calculate the result:

`(12 - 3color(red)(y))/2 + v(2color(red)(y) - 4)/color(red)(y)` becomes:

`(12 - (3 xx color(red)(3)))/2 + v((2 xx color(red)(3)) - 4)/color(red)(3) =>`

`(12 - 9)/2 + v(6 - 4)/color(red)(3) =>`

`3/2 + v2/3 =>`

`3/2 + 2/3v`