Question

In triangle `ABC`, `B=10` and `C=sqrt157`. If `C` is the hypotenuse, what is the measure of `A`?

Answer 1

`sqrt57`

Explanation:

We know, in a right angle triangle,`( hypotenuse)^2 = (base)^2+(height)^2`

So, `C^2 = A^2 + B^2`

`rArr (sqrt157)^2 = A^2+(10)^2`

`rArr 157 = A^2+100`

`rArr A^2 = 157-100 =57`

`rArr A = sqrt57`