Question #98339

2 Answers
Jun 1, 2017

n(O_2):n(SO_2) = 2:1

Explanation:

Molar mass of O_2: 2*16=32 (g/mol)
Molar mass of SO_2: 1*32 (one sulfur atom) + 2*16 (two oxygen atoms) = 64 (g/mol)

Number of molecules in each gram of substance:
O_2: 1/32
SO_2: 1/64

(n(O_2))/(n(SO_2)) = (1/32)/(1/64) = 2/1

2 : 1

Explanation:

Molar Mass of O_2 = 32 g mol^-1
rArr 1 g of O_2 = 1/32 mol

And Molar Mass of SO_2 = 32 + 2 * 16 g mol^-1 = 64 g mol^-1
rArr 1 g of SO_2 = 1/64 mol

Hence, O_2 : SO_2
rArr 1/32 N_A : 1/64 N_A
rArr 2 : 1