Question

If `4.57*g` of glucose are dissolved in `25.2*g` of water, what are the mole fractions, `chi_"each component"`?

Answer 1

`"Mole fraction,"` `chi="Moles of solute"/"Total moles of solution"`

Explanation:

And thus the sum of the mole fractions must be equal to one.......

`chi_"glucose"=((4.75*g)/(180.16*g*mol^-1))/((4.75*g)/(180.16*g*mol^-1)+(25.2*g)/(18.01*g*mol^-1))=0.0185`

`chi_"water"=((25.2*g)/(18.01*g*mol^-1))/((4.75*g)/(180.16*g*mol^-1)+(25.2*g)/(18.01*g*mol^-1))=0.9815`

And these are dimensionless quantities............