Question

What is the molar quantity of a `458*g` mass of `"lead(II) sulfide"`?

Answer 1

Approx. `2*mol`.

Explanation:

The molar mass of `"lead sulfide"` is `239.3*g*mol^-1`.

And to get the molar quantity of the given mass of lead sulfide, we take the quotient.

`"Moles of lead sulfide"="Mass"/"Molar mass"=(458*g)/(239.3*g*mol^-1)=`

`1.91*mol`.

This is dimensionally consistent because `(458*g)/(239.3*g*mol^-1)=`

`cancelg/(cancelg*mol^-1)=1/(1/(mol))=mol` as required..............