How do you solve the system of equations #3x - 6y = - 9# and #- 6x + 10y = 6#?

1 Answer
Jun 2, 2017

refer below.

Explanation:

Solve the equations simultaneously.

Firstly, choose 1 equation and make either #x# or #y# the subject.

#3x-6y=-9#

#3x=-9+6y#

#color(red)x=-3+2y# ------- (1) Let this be equation 1.

#-6color(red)x+10y=6# ------(2) Let this be equation 2.

Notice both equations have #x#?

Substitute (1) into (2).

#-6(-3+2y)+10y=6#
The #x# has been eliminated, and #y# can now be found.

#18-12y+10y=6#

#-12y+10y=6-18#

#-2y=-12#

#color(blue)(y=6)#

Since #y=6#, we can substitute this #y# value into (1).

#x=-3+2(6)#

#color(red)(x=9)#

When the #x# and #y# values are found, be sure to double check whether the answers satisfy the original equations.

When #y=6# and #x=9#,

#3x-6y=-9#

#3(9) - 6(6) = -9#

#27-36=-9#

#-9=-9#

Since both sides of the equation match, the answers are correct.