How do you write #-7y - 10x + 11 = 0# in standard form?

1 Answer
Jun 2, 2017

See a solution process below:

Explanation:

The standard form of a linear equation is: #color(red)(A)x + color(blue)(B)y = color(green)(C)#

Where, if at all possible, #color(red)(A)#, #color(blue)(B)#, and #color(green)(C)#are integers, and A is non-negative, and, A, B, and C have no common factors other than 1

First, subtract #color(red)(11)# from each side of the equation to isolate the #x# and #y# terms on the left side of the equation and the constant on the right side of the equation while keeping the equation balanced:

#-7y - 10x + 11 - color(red)(11) = 0 - color(red)(11)#

#-7y - 10x + 0 = -11#

#-7y - 10x = -11#

Next, rearrange the terms on the left side of the equation so the #x# term is first:

#-10x - 7y = -11#

Now, multiply each side of the equation by #color(red)(-1)# so the coefficient of the #x# term is non-negative while keeping the equation balanced:

#color(red)(-1)(-10x - 7y) = color(red)(-1) xx -11#

#(color(red)(-1) xx -10x) + (color(red)(-1) xx -7y) = 11#

#color(red)(10)x + color(blue)(7)y = color(green)(11)#