What is the force, in terms of Coulomb's constant, between two electrical charges of #14 C# and #9 C# that are #4 m # apart?

1 Answer
Jun 3, 2017

From Coulomb's law,

#F = k(q_1q_2)/r^2#

Where symbols have their usual meanings.

The force acts along the line joining the charges and is repulsive if the charges are of same signs, and attractive if they are of opposite signs.

Thus for the given charges,

#F = (9 * 10^9 * 14 * 9)/16 N#

Simplification gives,

#F = 70.875 * 10^9 N#

Which is, #F = 7.0875 * 10^10 N#

In terms of #k#,

#F = 7.875*k# units.