How do you solve #(2x)/3 = 5+ 6+ 1#?

1 Answer
Jun 4, 2017

See a solution process below:

Explanation:

First, combine the terms on the right side of the equation:

#(2x)/3 = 5 + 6 +1#

#(2x)/3 = 12#

Next, multiply each side of the equation by #color(red)(3)/color(blue)(2)# to solve for #x# while keeping the equation balanced:

#color(red)(3)/color(blue)(2) xx (2x)/3 = color(red)(3)/color(blue)(2) xx 12#

#cancel(color(red)(3))/cancel(color(blue)(2)) xx (color(blue)(cancel(color(black)(2)))x)/color(red)(cancel(color(black)(3))) = color(red)(3)/cancel(color(blue)(2)) xx color(blue)(cancel(color(black)(12)))6#

#x = 3 xx 6#

#x = 18#