Question

How do you solve `14- 3x = 28- 5x`?

Answer 1

See a solution process below:

Explanation:

First, add `color(red)(5x)` and subtract `color(blue)(14)` from each side of the equation to isolate the `x` term while keeping the equation balanced:

`-color(blue)(14) + 14 - 3x + color(red)(5x) = -color(blue)(14) + 28 - 5x + color(red)(5x)`

`0 + (-3 + color(red)(5))x = 14 - 0`

`2x = 14`

Now, divide each side of the equation by `color(red)(2)` to solve for `x` while keeping the equation balanced:

`(2x)/color(red)(2) = 14/color(red)(2)`

`(color(red)(cancel(color(black)(2)))x)/cancel(color(red)(2)) = 7`

`x = 7`