How do you solve #(x - 1) - ( 2x - 3) = \frac { 5x - 3} { 3}#?

1 Answer
Jun 6, 2017

See a solution process below:

Explanation:

First, group and combine like terms on the left side of the equation:

#x - 1 - 2x + 3 = (5x - 3)/3#

#x - 2x - 1 + 3 = (5x - 3)/3#

#1x - 2x - 1 + 3 = (5x - 3)/3#

#(1 - 2)x + (-1 + 3) = (5x - 3)/3#

#-1x + 2 = (5x - 3)/3#

#-x + 2 = (5x - 3)/3#

Next, multiply each side of the equation by #color(red)(3)# to eliminate the fraction while keeping the equation balanced:

#color(red)(3)(-x + 2) = color(red)(3) xx (5x - 3)/3#

#(color(red)(3) xx -x) + (color(red)(3) xx 2) = cancel(color(red)(3)) xx (5x - 3)/color(red)(cancel(color(black)(3)))#

#-3x + 6 = 5x - 3#

Then, add #color(red)(3x)# and #color(blue)(3)# to each side of the equation to isolate the #x# term while keeping the equation balanced:

#color(red)(3x) - 3x + 6 + color(blue)(3) = color(red)(3x) + 5x - 3 + color(blue)(3)#

#0 + 9 = (color(red)(3) + 5)x - 0#

#9 = 8x#

Now, divide each side of the equation by #color(red)(8)# to solve for #x# while keeping the equation balanced:

#9/color(red)(8) = (8x)/color(red)(8)#

#9/8 = (color(red)(cancel(color(black)(8)))x)/cancel(color(red)(8))#

#9/8 = x#

#x = 9/8#