Points A and B are at #(3 ,5 )# and #(2 ,5 )#, respectively. Point A is rotated counterclockwise about the origin by #(3pi)/2 # and dilated about point C by a factor of #3 #. If point A is now at point B, what are the coordinates of point C?

1 Answer
Jun 6, 2017

The coordinates of point are #C=(13/2,-7)#

Explanation:

The matrix of a rotation counterclockwise by #3/2pi# about the origin is

#((0,1),(-1,0))#

Therefore, the trasformation of point #A# is

#A'=((0,1),(-1,0))((3),(5))=((5),(-3))#

Let point #C# be #(x,y)#, then

#vec(CB)=3 vec(CA')#

#((2-x),(5-y))=3((5-x),(-3-y))#

So,

#2-x=3(5-x)#

#15-3x=2-x#

#2x=13#

#x=13/2#

and

#5-y=3(-3-y)#

#-9-3y=5-y#

#2y=-14#

#y=-7#

Therefore,

point #C=(13/2,-7)#