How do you solve #5f ^ { 2} - f - 6= 0#?

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Answer 1 · 2017-06-06T12:38:37

See a solution process below:

First, factor the quadratic as:

#(5f - 6)(f + 1) = 0#

Now, solve each term on the left for #0#:

Solution 1)

#5f - 6 = 0#

#5f - 6 + color(red)(6) = 0 + color(red)(6)#

#5f - 0 = 6#

#5f = 6#

#(5f)/color(red)(5) = 6/color(red)(5)#

#(color(red)(cancel(color(black)(5)))f)/cancel(color(red)(5)) = 6/5#

#f = 6/5#

Solution 2)

#f + 1 = 0#

#f + 1 - color(red)(1) = 0 - color(red)(1)#

#f + 0 = -1#

#f = -1#