Question #9f7ef

1 Answer
Jun 6, 2017

Q1. The minimum molecular mass of the compound is 330 u. Q2. There are 3 atoms of #"N"# and 1 atom of #"S"# per atom of #"Na"#.

Explanation:

Q1. Minimum molecular mass

There must be at least one atom of #"Na"# in methyl orange (MeO).

∴ The minimum molecular mass (MMM) is

#"MMM" = 1 color(red)(cancel(color(black)("atom Na"))) × (22.99 color(red)(cancel(color(black)("u Na"))))/(1 color(red)(cancel(color(black)("atom Na")))) × "100 u MeO"/(7 color(red)(cancel(color(black)("u Na")))) = "330 u MeO"#

Q2. Atoms of #"N"# and #"S"#.

#"Mass of N" = 330 color(red)(cancel(color(black)("u MeO"))) × "12.8 u N"/(100 color(red)(cancel(color(black)("u MeO")))) = "42 u N"#

#"Atoms of N" = 42 color(red)(cancel(color(black)("u"))) × "1 atom N"/(14.01 color(red)(cancel(color(black)("u")))) = "3 atoms N"#

#"Mass of S" = 330 color(red)(cancel(color(black)("u MeO"))) × "9.8 u S"/(100 color(red)(cancel(color(black)("u MeO")))) = "32 u S"#

#"Atoms of S" = 32 color(red)(cancel(color(black)("u"))) × "1 atom S"/(32.06 color(red)(cancel(color(black)("u")))) = "1 atom S"#