A container has #16 L# of water in it at #100 ^o C#. An object with a specific heat of #50 (KJ)/(Kg*K)# and a temperature of #180 ^oC# is placed into the container. If the water is completely vaporized, what is the object's mass?

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Answer 1 · 2017-06-07T08:01:01

The mass of the object is #=9.03kg#

The heat transferred from the hot object to the water, is equal to the heat used to evaporate the water.

For the rocks #DeltaT_o=180-100=80º#

Heat of vaporisation of water

#H_w=2257kJkg^-1#

The specific heat of the object is

#C_o=50kJkg^-1K^-1#

The mass of water is #m_w=16kg#

# m_o C_o (DeltaT_o) = m_w H_w #

#m_o*50*80=16*2257#

The mass of the object is

#m_o=(16*2257)/(50*80)#

#=9.03kg#