How do you solve $6 x - 45 = - 5 (x - 2)$ $6x - 45= - 5( x - 2)$ ?

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Answer 1 · 2017-06-07T13:02:24

$x = 5$ $x=5$

The first step is to distribute $- 5 (x - 2)$ $-5(x-2)$ .
Which is $- 5 x + 10$ $-5x+10$ .
Now we have this:

$6 x - 45 = - 5 x + 10$ $6x-45=-5x+10$

To solve this you add $5 x$ $5x$ to both sides, the $5 x$ $5x$ on the right cancels out.

$6 x + 5 x - 45 = 10$ $6x+5x-45=10$

Then you add $45$ $45$ to both sides the $45$ $45$ on the left cancels out.

$11 x = 10 + 45$ $11x=10+45$

Now you are left with:

$11 x = 55$ $11x=55$

Divide both by sides by $11$ $11$ and you get:

$x = 5$ $x=5$

How do you solve 6x - 45= - 5( x - 2)6x−45=−5(x−2)6x - 45= - 5( x - 2)?