How do you solve #\frac { x } { x - 3} = \frac { 8} { x - 2}#?

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Answer 1 · 2017-06-07T23:57:01

#x=-2,12#

The first step is cross multiple:

#x(x-2)=8(x-3)#

Distribute:

#x^2-2x=8x-24#

Then subtract #-8x# from both side and add #24# to both sides.

#x^2-2x-8x+24=0#

Simplify:

#x^2-10x+24#

Factor and set the factors equal to zero:

#(x-12)(x-2)=0#

Solve and you get:

#x=-2,12#