How do you find the limit of $x^2 + 7x + 10$ as x approaches $-2$ ?

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Answer 1 · 2017-06-08T10:01:32

$0$

We have: $lim_(x -> - 2) x^(2) + 7 x + 10$

In this case, we can simply substitute the value of $x$ into the expression to evaluate the limit:

$= (- 2)^(2) + 7 (- 2) + 10$

$= 4 - 14 + 10$

$= - 10 + 10$

$= 0$

Answer 2 · 2017-06-08T10:40:47

$0$

$"the limit of polynomials can be evaluated by substitution"$

$rArrlim_(xto-2)(x^2+7x+10)$

$=4-14+10$

$=0$

How do you find the limit of x^2 + 7x + 10x^2 + 7x + 10 as x approaches -2-2?