How do you find the limit of #x^2 + 7x + 10# as x approaches #-2#?

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Answer 1 · 2017-06-08T10:01:32

#0#

We have: #lim_(x -> - 2) x^(2) + 7 x + 10#

In this case, we can simply substitute the value of #x# into the expression to evaluate the limit:

#= (- 2)^(2) + 7 (- 2) + 10#

#= 4 - 14 + 10#

#= - 10 + 10#

#= 0#

Answer 2 · 2017-06-08T10:40:47

#0#

#"the limit of polynomials can be evaluated by substitution"#

#rArrlim_(xto-2)(x^2+7x+10)#

#=4-14+10#

#=0#