How do you solve #0.6x ^ { 2} = 1.2x + 0.6#?

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Answer 1 · 2017-06-08T19:54:40

Multiply everything by 10 Then set up a trinomial that can be solved by grouping

# 10{ 0.6x^2 = 1.2 x + 0.6} = 6x^2 = 12x + 6#

Move 12x and 6 to the other side by subtracting.

# 6x^2 -12x -6 = 12x -12 x + 6 -6# Which gives

# 6x^2 - 12x -6 = 0 # group this into two binomials

# x -1)(6x -6) = 0 # solve each binomial for x

# x - 1 = 0 # add 1 to both sides.

# x -1 + 1 = 0 + 1 # gives

x = 1

# 6x - 6 = 0 # add 6 to both sides

# 6x -6 +6 = 0 + 6 # which gives.

# 6x = 6 # divide both sides by 6

# 6x/6 = 6/6# gives

x = 1