How do you solve the system of equations by substitution #y= -2# and #4x - 3y =18#?

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Answer 1 · 2017-06-09T01:45:18

#x=3,y=-2#

Substitute the given #y#-value into #4x-3y=18# and solve for #x#

If #y=-2# then,

#4x-3(-2)=18#

#4x+6=18#

#4x+cancel(6-6)=18-6#

#4x=12#

#cancel(4/4)x=12/4#

#x=3#

The solution to the system of equations is thus: #x=3,y=-2#