How do you evaluate #(5-w)^2+x# if w=6, x=0.4, y=1/2, z=-3?
1 Answer
Jun 9, 2017
Explanation:
#"substitute the given values into the expression"#
#rArr(5color(red)(-6))^2+color(magenta)(0.4)#
#=(-1)^2+0.4#
#=1+0.4#
#=1.4#
