Question

How do you multiply `(x^(3/2) + 2/sqrt3)^2`?

Answer 1

See a solution process below:

Explanation:

This is a special form of quadratic:

`(a + b)^2 = a^2 + 2ab + b^2`

Substituting `x^(3/2)` for `a` and `2/sqrt(3)` for `b` gives:

`(x^(3/2) + b)^2 = (x^(3/2))^2 + (2 * x^(3/2) * 2/sqrt(3)) + (2/sqrt(3))^2 =`

`x^3 + (4x^(3/2))/sqrt(3) + 4/3`