A particle moves along X direction with constant acceleration. it velocity after 4s is 18 m/s and displacement is 56m find out its initial velocity and acceleration?

1 Answer
Jun 10, 2017

Initial velocity: 10ms

Acceleration: 2ms2

Explanation:

We're asked to find the initial velocity v0x and the acceleration ax of an particle moving in one dimension with a known velocity and position at a certain time.

To find the initial velocity, we can use the equation

x=x0+(vx+v0x2)t

We'll take the initial position x0 to be 0. Let's rearrange this equation to solve for the initial velocity v0x:

xt=vx+v0x2

v0x=2xtvx

Plugging in known values, we have

v0x=2(56m)4s18ms=10ms

The initial velocity is thus 10ms.

Now that we know the initial velocity, we can use the equation

vx=v0x+axt

to find its acceleration. Rearranging the equation to solve for ax, and plugging in known values, we have

ax=vxv0xt=18ms10ms4s=2ms2

The acceleration of the particle is thus constant at 2ms2.