How do you solve #90x+3=40x+150#?

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Answer 1 · 2017-06-11T00:30:05

See a solution process below:

Step 1) Subtract #color(red)(3)# and #color(blue)(40x)# from each side of the equation to isolate the #x# term while keeping the equation balanced:

#-color(blue)(40x) + 90x + 3 - color(red)(3) = -color(blue)(40x) + 40x + 150 - color(red)(3)#

#(-color(blue)(40) + 90)x + 0 = 0 + 147#

#50x = 147#

Step 2) Divide each side of the equation by #color(red)(50)# to solve for #x# while keeping the equation balanced:

#(50x)/color(red)(50) = 147/color(red)(50)#

#(color(red)(cancel(color(black)(50)))x)/cancel(color(red)(50)) = 147/50#

#x = 147/50#