If a projectile is shot at a velocity of 23 m/s and an angle of pi/12, how far will the projectile travel before landing?
1 Answer
Explanation:
We're asked to find the horizontal range of the launched projectile with a known initial velocity.
To find this distance, we first must find the time
where
-
Deltay is the change in height of the projectile, in"m" , -
v_(0y) is the initialy -velocity, in"m"/"s" . To find this, we must use the equation
v_(0y) = v_0sinalpha where
v_0 is the initial speed (23"m"/"s" ), and
alpha is the initial launch angle (pi/12 )Therefore, the initial
y -velocity is
v_(0y) = (23"m"/"s")sin(pi/12) = 5.95"m"/"s"
-
t is the time, in"s" , and -
g is the acceleration due to gravity near Earth's surface,9.8"m"/("s"^2)
Plugging in
Now, to find how far horizontally it traveled, we use the equation
We must find the initial
The horizontal range is thus
rounded to